Intermolecular Forces

What forces hold molecules together, and how do they explain boiling points and solubility?

IntermediateStates of Matter & GasesLast reviewed 5 October 2026

What is it?

Intermolecular forces are the attractions between molecules. They are different from the covalent bonds within a molecule (intramolecular forces), and much weaker: boiling water needs 40.7 kJ/mol to separate the molecules, but breaking an O–H bond inside a water molecule needs about 463 kJ/mol.

When a liquid boils, only the intermolecular forces are overcome; the molecules themselves stay intact. So the stronger the intermolecular forces, the higher the boiling point.

There are three main types, from weakest to strongest (for molecules of similar size):

  • London dispersion forces: present between all molecules. Electrons move constantly, creating brief, temporary dipoles that induce dipoles in neighbouring molecules. They grow with the number of electrons (larger molecules) and with surface contact (long, unbranched shapes).
  • Dipole–dipole forces: between polar molecules, which have permanent dipoles. The δ+ end of one molecule attracts the δ− end of another.
  • Hydrogen bonds: a strong dipole–dipole attraction between an H atom bonded to N, O or F and a lone pair on an N, O or F atom of another molecule.

Key idea

To predict boiling points, ask three questions. Is there an H on N, O or F? Then hydrogen bonding. Is the molecule polar? Then dipole–dipole forces. How big is it? Larger molecules have stronger dispersion forces, which can outweigh the other two.

Why does it matter?

  • States of matter. Intermolecular forces decide whether a substance is a gas, liquid or solid at room temperature, and its melting and boiling points.
  • Water and life. Hydrogen bonding gives water its high boiling point, high heat capacity and surface tension, makes ice float, and holds the two strands of DNA together.
  • Solubility and separation. “Like dissolves like” and chromatography both depend on matching intermolecular forces.

How does it work?

1. Dispersion forces and molecular size

The halogens are non-polar, so they have only dispersion forces. As the molecules get bigger and have more electrons, the dispersion forces grow and the boiling points rise:

HalogenMolar massBoiling pointState at 25 °C
FX2\ce{F2}38.00 g/mol−188 °Cgas
ClX2\ce{Cl2}70.90 g/mol−34 °Cgas
BrX2\ce{Br2}159.80 g/mol59 °Cliquid
IX2\ce{I2}253.80 g/mol184 °Csolid

Shape matters too: unbranched pentane (36 °C) boils higher than compact 2,2-dimethylpropane (10 °C), because long molecules touch over a larger area.

2. Comparing molecules of similar size

When molar masses are similar, dispersion forces are similar, and the other forces decide:

CompoundMolar massStrongest forceBoiling point
butane, CHX3CHX2CHX2CHX3\ce{CH3CH2CH2CH3}58.12 g/moldispersionabout 0 °C
propanone, CHX3COCHX3\ce{CH3COCH3}58.08 g/moldipole–dipole56 °C
propan-1-ol, CHX3CHX2CHX2OH\ce{CH3CH2CH2OH}60.10 g/molhydrogen bonding97 °C

3. Hydrogen bonding

Hydrogen bonding is unusually strong because N, O and F are very electronegative and small, and the H atom has no inner electrons, so its nucleus is exposed. Each water molecule can form up to four hydrogen bonds (two through its H atoms and two through its lone pairs). That is why:

  • water (18.02 g/mol) boils at 100 °C, while HX2S\ce{H2S} (34.08 g/mol) boils at −60 °C;
  • ice floats: in ice, hydrogen bonds hold the molecules in an open hexagonal network, so ice is less dense than liquid water.

4. Effects on properties

Stronger intermolecular forces mean:

  • higher melting and boiling points and a larger enthalpy of vaporization;
  • lower vapour pressure (fewer molecules escape from the liquid);
  • higher viscosity and surface tension.

For solubility, a solute dissolves best in a solvent with similar forces: polar and hydrogen-bonding substances (sugar, ethanol) dissolve in water; non-polar substances (oil, iodine) dissolve in non-polar solvents such as hexane. Ionic compounds dissolve in water through ion–dipole attractions.

Think of it like this

Think of molecules as people in a crowded room. Dispersion forces are a light brush of shoulders: weak, but they add up when people are big and pressed close together. Dipole–dipole forces are like people turning to face each other. Hydrogen bonds are firm handshakes. The more handshakes, the harder it is for anyone to leave the room, just as more hydrogen bonding makes a liquid harder to boil.

More precisely

Dispersion forces are not always the weakest overall: a large non-polar molecule can have stronger total attractions than a small polar one. Iodine (IX2\ce{I2}, 184 °C) boils far higher than water, despite having no dipole. A hydrogen bond is typically 10 to 40 kJ/mol, compared with roughly 150 to 1000 kJ/mol for covalent bonds. In proteins, hydrogen bonds between different parts of the chain hold the shapes (helices and sheets) that make the protein work.

Visualise it

Five water molecules. The central water molecule's oxygen is labelled δ− and its two hydrogens δ+. Dashed blue lines show hydrogen bonds: each δ+ hydrogen of the central molecule points to the oxygen of a molecule below, and hydrogens of two other molecules point to the central oxygen. Solid lines are covalent O–H bonds. Each water molecule can form up to four hydrogen bonds.
Dashed lines are hydrogen bonds: much weaker than the covalent O–H bonds, but strong for an intermolecular force.
A graph of boiling point against period for two groups of hydrides. Group 14: CH4 −162, SiH4 −112, GeH4 −88 and SnH4 −52 °C rise steadily with size. Group 16: H2S −60, H2Se −41 and H2Te −2 °C also rise, but H2O at 100 °C is far above the trend. Extending the trend, water would boil at about −80 °C.
Boiling points rise with molecular size (dispersion forces), except for water, which hydrogen bonding lifts far above the trend.

Worked example

Worked example: Identifying intermolecular forces

Question: Name all the intermolecular forces in (a) CHX4\ce{CH4} (b) HCl\ce{HCl} (c) NHX3\ce{NH3} (d) COX2\ce{CO2}.

  1. (a) Non-polar: dispersion forces only.
  2. (b) Polar (Cl is more electronegative than H), but H is not on N, O or F: dispersion + dipole–dipole.
  3. (c) H bonded to N, and N has a lone pair: dispersion + dipole–dipole + hydrogen bonding.
  4. (d) The C=O bonds are polar, but the linear molecule is symmetrical, so the dipoles cancel: dispersion forces only.

Worked example: Ranking boiling points

Question: Put butane, propanone and propan-1-ol in order of increasing boiling point, and explain.

  1. Their molar masses are almost equal (58 to 60 g/mol), so their dispersion forces are similar.
  2. Butane is non-polar: dispersion only. Lowest.
  3. Propanone has a polar C=O group: dipole–dipole forces as well. Middle.
  4. Propan-1-ol has an O–H group: hydrogen bonding as well. Highest.
  5. Order, lowest first: butane (about 0 °C), propanone (56 °C), propan-1-ol (97 °C).

Worked example: Energy to boil water

Question: How much energy is needed to vaporize 25.0 g of water at 100 °C? (ΔHvap\Delta H_\text{vap} = 40.7 kJ/mol; HX2O\ce{H2O} = 18.02 g/mol)

  1. n=25.0 g18.02 g/mol=1.387 moln = \dfrac{25.0\ \text{g}}{18.02\ \text{g/mol}} = 1.387\ \text{mol}
  2. q=n×ΔHvap=1.387 mol×40.7 kJ/mol=q = n \times \Delta H_\text{vap} = 1.387\ \text{mol} \times 40.7\ \text{kJ/mol} = 56.5 kJ
  3. This energy only separates the molecules (overcoming hydrogen bonds and other intermolecular forces); no O–H bonds are broken, and the steam is still HX2O\ce{H2O}.

Common mistake

Common mistake: Thinking boiling breaks covalent bonds

When water boils, the bubbles contain HX2O\ce{H2O} molecules, not hydrogen and oxygen. Boiling overcomes intermolecular forces; the covalent bonds inside the molecules are untouched.

Common mistake: Calling any H-containing molecule hydrogen-bonded

Hydrogen bonding needs H bonded directly to N, O or F. CHX4\ce{CH4} and the C–H hydrogens in ethanol do not form hydrogen bonds; only ethanol’s O–H hydrogen does.

Common mistake: Forgetting dispersion forces

Every molecule has dispersion forces, including polar ones. For large molecules they are often the largest contribution: that is why iodine is a solid and HBr\ce{HBr} boils higher than HCl\ce{HCl}.

Notation note

  • London dispersion forces are also called London forces, dispersion forces or instantaneous dipole–induced dipole forces. Together with dipole–dipole forces they are often called van der Waals forces.
  • A hydrogen bond is usually drawn as a dashed line: O–H⋯O.
  • δ+ and δ− mean partial positive and partial negative charges.

Remember this

Remember this

  • Intermolecular forces act between molecules; they are much weaker than covalent bonds. Boiling overcomes only these forces.
  • For molecules of similar size, weakest to strongest: dispersion (all molecules; bigger and longer = stronger), dipole–dipole (polar molecules), hydrogen bonding (H on N, O or F).
  • Stronger forces: higher boiling point, lower vapour pressure, higher viscosity and surface tension.
  • Like dissolves like; hydrogen bonding explains water’s high boiling point and why ice floats.

Test yourself

Check your understanding before moving on.

Flashcards

Intermolecular Forces: Flashcards

10 cards

  1. Question
    Intermolecular force vs covalent bond?
    Answer

    Intermolecular forces act between molecules and are much weaker; covalent bonds hold atoms together within a molecule.

  2. Question
    What are London dispersion forces?
    Answer

    Attractions between temporary dipoles caused by moving electrons. Present in all molecules; stronger for bigger, longer molecules.

  3. Question
    When do dipole–dipole forces occur?
    Answer

    Between polar molecules: the δ+ end of one attracts the δ− end of another.

  4. Question
    What is needed for hydrogen bonding?
    Answer

    An H atom bonded to N, O or F, and a lone pair on an N, O or F atom of another molecule.

  5. Question
    What is overcome when a molecular liquid boils?
    Answer

    Only the intermolecular forces; covalent bonds inside the molecules stay intact.

  6. Question
    Why does water (100 °C) boil so much higher than H₂S (−60 °C)?
    Answer

    Water forms hydrogen bonds (O–H); H₂S does not, and has only weaker dipole–dipole and dispersion forces.

  7. Question
    Why does pentane boil higher than 2,2-dimethylpropane?
    Answer

    Unbranched pentane has more surface contact, so stronger dispersion forces (36 °C against 10 °C).

  8. Question
    Why does ice float?
    Answer

    Hydrogen bonds hold the molecules in an open network in ice, so ice is less dense than liquid water.

  9. Question
    How do stronger intermolecular forces affect vapour pressure and viscosity?
    Answer

    Vapour pressure is lower; viscosity and surface tension are higher.

  10. Question
    What does "like dissolves like" mean?
    Answer

    Solutes dissolve best in solvents with similar forces: polar in polar (water), non-polar in non-polar (hexane).

Quiz

Intermolecular Forces: Quiz

7 questions

  1. Question 1EasyWhich forces are present between CH₄ molecules?
    Show answer

    Answer: dispersion forces only

    Methane is non-polar and has no H on N, O or F, so only dispersion forces act.

  2. Question 2EasyWhich molecule can form hydrogen bonds with itself?
    Show answer

    Answer: CH₃OH

    Methanol has an H bonded directly to O. In CH₃OCH₃ all H atoms are on carbon.

  3. Question 3EasyWhich halogen has the highest boiling point?
    Show answer

    Answer: I₂

    All are non-polar; I₂ has the most electrons and the strongest dispersion forces (184 °C).

  4. Question 4MediumWhich has the highest boiling point: butane, propanone or propan-1-ol (all about 58–60 g/mol)?
    Show answer

    Answer: propan-1-ol

    With similar dispersion forces, propan-1-ol wins because it can hydrogen-bond (97 °C, against 56 °C and about 0 °C).

  5. Question 5HardCO₂ has polar C=O bonds. What are its intermolecular forces?
    Show answer

    Answer: dispersion forces only

    CO₂ is linear, so the two bond dipoles cancel and the molecule is non-polar.

  6. Question 6MediumWhich is most soluble in hexane?
    Show answer

    Answer: I₂

    Like dissolves like: non-polar iodine dissolves in non-polar hexane.

  7. Question 7MediumHow much energy is needed to vaporize 2.00 mol of water at 100 °C (ΔH(vap) = 40.7 kJ/mol)?
    Show answer

    Answer: 81.4 kJ

    q = 2.00 mol × 40.7 kJ/mol = 81.4 kJ.

Notes and downloads

  • Worksheet

    Intermolecular Forces Worksheet

    9 questions on identifying intermolecular forces, explaining boiling points, ice and solubility, and enthalpy of vaporization. Answer key included.

    IntermediateFree

References

  1. Brown, T. L.; LeMay, H. E., Jr.; Bursten, B. E.; Murphy, C. J.; Woodward, P. M.; Stoltzfus, M. W. Chemistry: The Central Science, 15th ed.; Pearson, 2022.

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