Radioactive Decay and Half-Life

What are alpha, beta and gamma decay, and how do you use half-life?

IntermediateNuclear ChemistryLast reviewed 4 October 2026

What is it?

Most nuclei are stable, but some have an unstable combination of protons and neutrons. An unstable nucleus decays: it changes into a different nucleus and gives out radiation. This is radioactivity, and it happens on its own, whatever the temperature, pressure or chemical form of the atom.

A nucleus is written in nuclide notation, with the mass number A (protons + neutrons) at the top left and the atomic number Z (protons) at the bottom left:

X92238X2922238U\ce{^{238}_{92}U}

Uranium-238 has 92 protons and 238 − 92 = 146 neutrons.

The main types of radiation are:

RadiationSymbolWhat it isEffect on the nucleus
Alpha (α)X24X2224He\ce{^{4}_{2}He}2 protons + 2 neutronsA − 4, Z − 2
Beta (β⁻)X−10X2−120e\ce{^{0}_{-1}e}a fast electronA same, Z + 1
Positron (β⁺)X+10X2+120e\ce{^{0}_{+1}e}a positive electronA same, Z − 1
Gamma (γ)X00X2020γ\ce{^{0}_{0}\gamma}high-energy lightno change in A or Z

Key idea

In every nuclear equation, the mass numbers add up to the same total on both sides, and so do the atomic numbers. Use these two sums to find any missing particle or nucleus.

Why does it matter?

  • Medicine. Technetium-99m is used for medical imaging, fluorine-18 for PET scans, and iodine-131 and cobalt-60 to treat cancer.
  • Dating. Carbon-14 dates objects up to about 50 000 years old; uranium and potassium isotopes date rocks billions of years old.
  • Safety and energy. Radon gas from rocks is a health hazard in some homes, and nuclear power stations depend on radioactive fuels and produce radioactive waste.

How does it work?

1. Types of decay

  • Alpha decay: a heavy nucleus emits a helium nucleus. X88226X2882226Ra→X86222X2862222Rn+X24X2224He\ce{^{226}_{88}Ra -> ^{222}_{86}Rn + ^{4}_{2}He}
  • Beta decay: a neutron turns into a proton and an electron, and the electron is emitted. X614X26214C→X714X27214N+X−10X2−120e\ce{^{14}_{6}C -> ^{14}_{7}N + ^{0}_{-1}e}
  • Positron emission: a proton turns into a neutron and a positron. X918X29218F→X818X28218O+X+10X2+120e\ce{^{18}_{9}F -> ^{18}_{8}O + ^{0}_{+1}e}
  • Gamma emission: a nucleus with excess energy releases it as a gamma ray, often just after alpha or beta decay. The element does not change.

2. Balancing a nuclear equation

  1. Write the parent nucleus on the left and the known products on the right.
  2. Mass numbers: top numbers on the left = top numbers on the right.
  3. Atomic numbers: bottom numbers on the left = bottom numbers on the right.
  4. Use the atomic number of the unknown to find its symbol from the periodic table.

3. Penetrating power

Alpha particles are heavy and doubly charged: they ionize strongly but are stopped by a sheet of paper or the outer layer of skin. Beta particles get through paper but are stopped by a few millimetres of aluminium. Gamma rays are the most penetrating and are only reduced by thick lead or concrete. Alpha emitters are therefore most dangerous inside the body (if swallowed or inhaled).

4. Half-life

The half-life, t1/2t_{1/2}, is the time it takes for half of the radioactive nuclei in a sample to decay. After each half-life, the amount (and the activity, the number of decays per second) halves again:

N=N0(12)nn=tt1/2N = N_0 \left(\tfrac{1}{2}\right)^{n} \qquad n = \frac{t}{t_{1/2}}

where N0N_0 is the starting amount, NN the amount left after time tt, and nn the number of half-lives. The time and the half-life must be in the same unit, so nn has no unit. NN and N0N_0 can be masses, numbers of nuclei or activities, as long as both use the same unit.

When nn is not a whole number, solve for tt with logarithms:

t=t1/2×ln⁡(N0/N)ln⁡2t = t_{1/2} \times \frac{\ln(N_0/N)}{\ln 2}
NuclideHalf-life
fluorine-18110 min
technetium-99m6.01 h
radon-2223.82 d
iodine-1318.02 d
carbon-145730 yr
uranium-2384.47 × 10⁹ yr

5. Radiocarbon dating

Living things take in carbon-14 from the air, so the ratio of carbon-14 to carbon-12 in them stays constant. After death no new carbon-14 enters, and the carbon-14 decays with a half-life of 5730 years. Comparing the carbon-14 activity of a sample with that of living material gives its age.

Think of it like this

Half-life is like a bowl of popcorn kernels in which each kernel has the same chance of popping each minute. You can’t predict when one particular kernel pops, but you can say confidently that half of the kernels will have popped after a certain time, then half of the rest, and so on. In the same way, the decay of one nucleus is random, but a large sample follows the half-life exactly.

More precisely

Radioactive decay is a first-order process: the rate is proportional to the number of nuclei present, activity=kN\text{activity} = kN, with the decay constant k=ln⁡2/t1/2k = \ln 2 / t_{1/2}. Activity is measured in becquerels (1 Bq = 1 decay per second). Another decay mode, electron capture, pulls an inner electron into the nucleus, turning a proton into a neutron (Z − 1, A unchanged). Whether a nucleus is stable depends mainly on its neutron-to-proton ratio: too many neutrons favours beta decay, too few favours positron emission or electron capture, and very heavy nuclei (Z above 83) undergo alpha decay.

Visualise it

Radiation from a source travels towards three barriers. The alpha ray is stopped by paper. The beta ray passes through the paper but is stopped by aluminium a few millimetres thick. The gamma ray passes through paper and aluminium and is greatly reduced by several centimetres of lead, with a faint dotted line continuing beyond: gamma is only reduced, never fully stopped.
Alpha is stopped by paper, beta by a few millimetres of aluminium; gamma is only reduced by thick lead.
A decay curve of percent of nuclei remaining against time in half-lives. The curve starts at 100 percent and falls to 50 percent after 1 half-life, 25 percent after 2, 12.5 percent after 3 and 6.25 percent after 4, with dashed guide lines at each point. The formula is N = N0 × (1/2) to the power n, where n = t divided by the half-life.
Each half-life halves what is left: 100 %, 50 %, 25 %, 12.5 %, 6.25 %.

Worked example

Worked example: Completing nuclear equations

Question: Complete: (a) X92238X2922238U→?+X24X2224He\ce{^{238}_{92}U -> ? + ^{4}_{2}He} (b) X53131X2532131I→?+X−10X2−120e\ce{^{131}_{53}I -> ? + ^{0}_{-1}e}

  1. (a) Mass number: 238 = A + 4, so A = 234. Atomic number: 92 = Z + 2, so Z = 90, which is thorium: X90234X2902234Th\ce{^{234}_{90}Th}.
  2. (b) Mass number: 131 = A + 0, so A = 131. Atomic number: 53 = Z + (−1), so Z = 54, which is xenon: X54131X2542131Xe\ce{^{131}_{54}Xe}.

Worked example: A whole number of half-lives

Question: A hospital receives 80.0 mg of iodine-131 (t1/2t_{1/2} = 8.02 d). How much is left after 24.06 d?

  1. n=tt1/2=24.06 d8.02 d=3.00n = \dfrac{t}{t_{1/2}} = \dfrac{24.06\ \text{d}}{8.02\ \text{d}} = 3.00 (the days cancel)
  2. N=80.0 mg×(12)3.00=80.0 mg8=N = 80.0\ \text{mg} \times \left(\tfrac{1}{2}\right)^{3.00} = \dfrac{80.0\ \text{mg}}{8} = 10.0 mg

Worked example: Radiocarbon dating

Question: A piece of ancient wood has 35.0 % of the carbon-14 activity of living wood. How old is it? (t1/2t_{1/2} = 5730 yr)

  1. N0N=100.0 %35.0 %=2.857\dfrac{N_0}{N} = \dfrac{100.0\ \%}{35.0\ \%} = 2.857 (a ratio, so no unit)
  2. n=ln⁡2.857ln⁡2=1.0500.6931=1.515n = \dfrac{\ln 2.857}{\ln 2} = \dfrac{1.050}{0.6931} = 1.515 half-lives
  3. t=1.515×5730 yr=t = 1.515 \times 5730\ \text{yr} = 8.68 × 10³ yr (about 8680 years)
  4. Check: 35.0 % lies between 50 % (1 half-life) and 25 % (2 half-lives), so the age must be between 5730 yr and 11 460 yr. ✓

Common mistake

Common mistake: Thinking everything is gone after two half-lives

After one half-life, half is left; after two, a quarter (not zero). The amount approaches zero but, in a large sample, takes many half-lives to become negligible: after 10 half-lives, about 0.1 % remains.

Common mistake: Changing the mass number in beta decay

Beta decay changes a neutron into a proton, so the mass number stays the same and the atomic number goes up by 1. X614X26214C\ce{^{14}_{6}C} becomes X714X27214N\ce{^{14}_{7}N}, not X613X26213C\ce{^{13}_{6}C}.

Common mistake: Mixing time units

In n=t/t1/2n = t/t_{1/2}, both times must be in the same unit. For technetium-99m (t1/2t_{1/2} = 6.01 h) after 2.00 days, first convert: 2.00 d×24 h/d=48.0 h2.00\ \text{d} \times 24\ \text{h/d} = 48.0\ \text{h}.

Notation note

  • In nuclide notation the mass number is on top and the atomic number below: X614X26214C\ce{^{14}_{6}C}. In text, write carbon-14 or C-14.
  • A beta particle can be written X−10X2−120e\ce{^{0}_{-1}e} or X−10X2−120β\ce{^{0}_{-1}\beta}; an alpha particle X24X2224He\ce{^{4}_{2}He} or X24X2224α\ce{^{4}_{2}\alpha}.
  • The “m” in technetium-99m means “metastable”: an excited nucleus that releases gamma rays.

Remember this

Remember this

  • Alpha: A − 4, Z − 2. Beta (β⁻): A same, Z + 1. Positron (β⁺): A same, Z − 1. Gamma: no change.
  • Nuclear equations: mass numbers and atomic numbers both balance.
  • Penetration: alpha stopped by paper, beta by aluminium, gamma reduced by thick lead.
  • Half-life: N=N0(12)nN = N_0(\tfrac{1}{2})^{n} with n=t/t1/2n = t/t_{1/2} (same time units); for non-whole nn, t=t1/2×ln⁡(N0/N)/ln⁡2t = t_{1/2} \times \ln(N_0/N)/\ln 2.

Test yourself

Check your understanding before moving on.

Flashcards

Radioactive Decay and Half-Life: Flashcards

10 cards

  1. Question
    In nuclide notation, what do the top and bottom numbers mean?
    Answer

    Top: mass number A (protons + neutrons). Bottom: atomic number Z (protons). E.g. uranium-238: A = 238, Z = 92.

  2. Question
    What is an alpha particle, and how does alpha decay change the nucleus?
    Answer

    A helium-4 nucleus (2 protons + 2 neutrons). A decreases by 4, Z by 2.

  3. Question
    What happens in beta (β⁻) decay?
    Answer

    A neutron becomes a proton and an electron; the electron is emitted. A stays the same, Z increases by 1.

  4. Question
    What happens in positron (β⁺) emission?
    Answer

    A proton becomes a neutron and a positron is emitted. A stays the same, Z decreases by 1.

  5. Question
    What is gamma radiation?
    Answer

    High-energy electromagnetic radiation from an excited nucleus. A and Z do not change.

  6. Question
    What must balance in a nuclear equation?
    Answer

    The total mass number and the total atomic number on each side.

  7. Question
    What stops alpha, beta and gamma radiation?
    Answer

    Alpha: paper or skin. Beta: a few mm of aluminium. Gamma: only reduced by thick lead or concrete.

  8. Question
    Define half-life.
    Answer

    The time for half of the radioactive nuclei in a sample (and its activity) to decay.

  9. Question
    What fraction of a sample remains after 3 half-lives?
    Answer

    (½)³ = ⅛, i.e. 12.5 %.

  10. Question
    Equation for the amount left after time t?
    Answer

    N = N₀ × (½)ⁿ, where n = t ÷ t½ (t and t½ in the same unit).

Quiz

Radioactive Decay and Half-Life: Quiz

7 questions

  1. Question 1EasyHow many neutrons are in a nucleus of carbon-14 (Z = 6)?
    Show answer

    Answer: 8

    Neutrons = mass number − atomic number = 14 − 6 = 8.

  2. Question 2EasyRadium-226 (Z = 88) undergoes alpha decay. What is the product nucleus?
    Show answer

    Answer: radon-222 (Z = 86)

    Alpha decay removes 4 from A and 2 from Z: 226 − 4 = 222 and 88 − 2 = 86, which is radon.

  3. Question 3MediumIn ²³⁴₉₀Th → ²³⁴₉₁Pa + X, what is X?
    Show answer

    Answer: a beta particle (electron)

    A stays 234 and Z rises by 1, so X has A = 0 and Z = −1: an electron, ⁰₋₁e.

  4. Question 4EasyWhich radiation is stopped by a sheet of paper?
    Show answer

    Answer: alpha

    Alpha particles are heavy and doubly charged, so they lose their energy quickly. Beta needs aluminium; gamma is only reduced by thick lead.

  5. Question 5MediumA sample of 160 mg has a half-life of 2.0 h. How much is left after 6.0 h?
    Show answer

    Answer: 20 mg

    n = 6.0 h ÷ 2.0 h = 3.0 half-lives, so 160 mg × (½)³ = 20 mg.

  6. Question 6MediumThe activity of a sample falls from 1200 Bq to 300 Bq in 16 days. What is its half-life?
    Show answer

    Answer: 8 days

    1200 Bq → 600 Bq → 300 Bq is 2 half-lives, so t½ = 16 days ÷ 2 = 8 days.

  7. Question 7HardFluorine-18 (Z = 9) emits a positron. What is the product?
    Show answer

    Answer: oxygen-18 (Z = 8)

    Positron emission keeps A the same and lowers Z by 1: Z = 8 is oxygen, so ¹⁸₉F → ¹⁸₈O + ⁰₊₁e.

Notes and downloads

  • Worksheet

    Radioactive Decay and Half-Life Worksheet

    9 questions on nuclide notation, nuclear equations, types of radiation, half-life calculations and radiocarbon dating. Answer key included.

    IntermediateFree

References

  1. Brown, T. L.; LeMay, H. E., Jr.; Bursten, B. E.; Murphy, C. J.; Woodward, P. M.; Stoltzfus, M. W. Chemistry: The Central Science, 15th ed.; Pearson, 2022.

Spotted a mistake? Let us know and we'll fix it.