Nuclear Fission and Fusion

Where does nuclear energy come from, and how do fission and fusion differ?

IntermediateNuclear ChemistryLast reviewed 4 October 2026

What is it?

Nuclear reactions can release millions of times more energy than chemical reactions. They come in two kinds:

  • Fission: a heavy nucleus, such as uranium-235, splits into two medium-sized nuclei, releasing neutrons and energy.
  • Fusion: two light nuclei, such as isotopes of hydrogen, join to form a heavier nucleus, releasing energy.

The energy comes from mass. A nucleus has slightly less mass than the protons and neutrons that make it up. This missing mass, the mass defect (Δm\Delta m), was converted into energy when the nucleus formed, according to Einstein’s equation:

E=Δm c2E = \Delta m\, c^{2}

where cc = 2.998 × 10⁸ m/s is the speed of light. The same energy, the binding energy, would be needed to pull the nucleus apart again.

Key idea

Nuclei with a higher binding energy per nucleon are more stable. Iron-56 is near the top of the curve. Splitting very heavy nuclei (fission) or joining very light ones (fusion) moves towards iron, so both release energy.

Why does it matter?

  • Electricity. Nuclear power stations use controlled fission of uranium-235 and generate electricity without burning fuel or emitting carbon dioxide while they run.
  • The stars. The Sun shines by fusing hydrogen into helium; most elements up to iron were made by fusion in stars.
  • Future energy and risks. Fusion reactors are being developed as a cleaner energy source; fission produces long-lived radioactive waste, and both processes underlie nuclear weapons.

How does it work?

1. Mass defect and binding energy

  1. Add up the masses of the separate protons and neutrons.
  2. Subtract the measured mass of the nucleus: this is the mass defect, Δm\Delta m.
  3. Convert Δm\Delta m to kilograms (1 u = 1.66054 × 10⁻²⁷ kg) and use E=Δm c2E = \Delta m\,c^2. The units give kg m² s⁻² = J.
  4. Divide by the number of nucleons (protons + neutrons) to compare nuclei.

Nuclear energies are often given in mega-electronvolts: 1 MeV = 1.602 × 10⁻¹³ J.

2. Fission and the chain reaction

When uranium-235 absorbs a slow neutron, it splits. One of many possible splits is:

X01X2021n+X92235X2922235U→X56141X2562141Ba+X3692X236292Kr+3X01n\small \ce{^{1}_{0}n + ^{235}_{92}U -> ^{141}_{56}Ba + ^{92}_{36}Kr + 3^{1}_{0}n}

Each fission releases about 200 MeV and 2 or 3 neutrons. If at least one of these neutrons causes another fission, a chain reaction follows. The smallest mass of fuel that can keep the chain going is the critical mass.

A nuclear reactor controls the chain reaction:

  • Fuel rods: uranium enriched in uranium-235.
  • Moderator (water or graphite): slows the neutrons so they are captured by uranium-235 more easily.
  • Control rods (boron or cadmium): absorb neutrons; lowering them slows the reaction.
  • Coolant: carries the heat away to make steam, which drives turbines.

3. Fusion

Fusion needs temperatures of millions of degrees, so that the positively charged nuclei collide fast enough to overcome their repulsion. The most promising reaction for reactors fuses deuterium and tritium:

X12X2122H+X13X2123H→X24X2224He+X01X2021n\ce{^{2}_{1}H + ^{3}_{1}H -> ^{4}_{2}He + ^{1}_{0}n}

In the Sun, a series of steps has the overall effect 4X11H→X24X2224He+2X+10e\ce{4^{1}_{1}H -> ^{4}_{2}He + 2^{0}_{+1}e} (plus neutrinos and gamma rays).

FissionFusion
Nucleiheavy splitlight join
Fueluranium-235, plutonium-239hydrogen isotopes
Conditionsslow neutrons, critical massmillions of degrees
Wasteradioactive fission productsmainly helium (little long-lived waste)
Statuspower stations since the 1950sexperimental

Think of it like this

Think of nucleons as people in groups, where the most comfortable group size is medium (iron). People in a huge, crowded group (uranium) are happier if it splits in two; people in tiny groups (hydrogen) are happier if they join up. Either change makes everyone more comfortable, and the “relief” is released as energy.

More precisely

Chemical reactions also turn a tiny amount of mass into energy, but it is far too small to measure: about one part in 10¹⁰ of the mass, compared with about one part in 10³ in fission. Binding energy uses E=Δm c2E = \Delta m\,c^2 because the strong nuclear force holding nucleons together is far stronger than the electrical forces in chemical bonds. In a nuclear power station, the fuel contains only a few percent of uranium-235, which cannot explode like a bomb, but the reactor must still be cooled even after shutdown, because its fission products keep releasing decay heat.

Visualise it

A graph of binding energy per nucleon, in MeV, against mass number A from 0 to 240. The curve rises steeply from hydrogen-2 at about 1.1 MeV, with helium-4 standing out at about 7.1 MeV, to a maximum of about 8.8 MeV near iron-56, labelled most stable. It then falls slowly to about 7.6 MeV at uranium-235. A purple arrow labelled fusion points from the light nuclei up towards iron; an orange arrow labelled fission points from uranium up towards iron. Moving towards iron, from either side, releases energy.
Iron-56 is near the peak: fusion of light nuclei and fission of heavy ones both move up the curve and release energy.
A fission chain reaction. A neutron strikes a uranium-235 nucleus, which splits into two fission fragments and releases three neutrons. Each of these neutrons strikes another uranium-235 nucleus, which also splits into two fragments and releases more neutrons. A note says that control rods absorb neutrons to keep a reactor steady.
One neutron in, two or three out: each fission can trigger several more.

Worked example

Worked example: Binding energy of carbon-12

Question: A carbon-12 nucleus (6 protons, 6 neutrons) has a mass of 11.996709 u. Find its binding energy and its binding energy per nucleon. (proton 1.007276 u; neutron 1.008665 u)

  1. Mass of the separate nucleons: 6(1.007276 u)+6(1.008665 u)=12.095646 u6(1.007276\ \text{u}) + 6(1.008665\ \text{u}) = 12.095646\ \text{u}

  2. Mass defect: Δm=12.095646 u−11.996709 u=0.098937 u\Delta m = 12.095646\ \text{u} - 11.996709\ \text{u} = 0.098937\ \text{u}

  3. In kilograms:

    Δm=0.098937 u×1.66054×10−27 kgu=1.6429×10−28 kg\begin{aligned} &\Delta m = 0.098937\ \text{u} \\[4pt] &\quad \times 1.66054 \times 10^{-27}\ \tfrac{\text{kg}}{\text{u}} \\[4pt] &\quad = 1.6429 \times 10^{-28}\ \text{kg} \end{aligned}
  4. Energy:

    E=(1.6429×10−28 kg)×(2.998×108 m/s)2=1.477×10−11 J\begin{aligned} &E = (1.6429 \times 10^{-28}\ \text{kg}) \\[4pt] &\quad \times (2.998 \times 10^{8}\ \text{m/s})^{2} \\[4pt] &\quad = 1.477 \times 10^{-11}\ \text{J} \end{aligned}
  5. In MeV: 1.477×10−11 J1.602×10−13 J/MeV=92.17 MeV\dfrac{1.477 \times 10^{-11}\ \text{J}}{1.602 \times 10^{-13}\ \text{J/MeV}} = 92.17\ \text{MeV}; per nucleon: 92.17 MeV12=\dfrac{92.17\ \text{MeV}}{12} = 7.68 MeV per nucleon

Worked example: Energy from deuterium–tritium fusion

Question: Find the energy released per mole of helium formed in X12X2122H+X13X2123H→X24X2224He+X01X2021n\ce{^{2}_{1}H + ^{3}_{1}H -> ^{4}_{2}He + ^{1}_{0}n}. (²H 2.014102 u; ³H 3.016049 u; ⁴He 4.002603 u; n 1.008665 u)

  1. Mass before: 2.014102 u+3.016049 u=5.030151 u2.014102\ \text{u} + 3.016049\ \text{u} = 5.030151\ \text{u}

  2. Mass after: 4.002603 u+1.008665 u=5.011268 u4.002603\ \text{u} + 1.008665\ \text{u} = 5.011268\ \text{u}

  3. Δm=0.018883 u\Delta m = 0.018883\ \text{u} per reaction, so 0.018883 g per mole =1.8883×10−5= 1.8883 \times 10^{-5} kg/mol

  4. Energy:

    E=(1.8883×10−5 kgmol)×(2.998×108 m/s)2=1.697×1012 J/mol\begin{aligned} &E = (1.8883 \times 10^{-5}\ \tfrac{\text{kg}}{\text{mol}}) \\[4pt] &\quad \times (2.998 \times 10^{8}\ \text{m/s})^{2} \\[4pt] &\quad = 1.697 \times 10^{12}\ \text{J/mol} \end{aligned}
  5. That is 1.697 × 10⁹ kJ/mol, about two million times the 890 kJ/mol released by burning methane.

Common mistake

Common mistake: Thinking mass is lost and energy appears from nowhere

Mass and energy are two forms of the same thing. The products of a nuclear reaction have slightly less mass, and the missing mass appears as the kinetic energy of the products and as radiation. Total mass-energy is conserved.

Common mistake: Forgetting to convert u to kg

E=Δm c2E = \Delta m\,c^2 gives joules only when Δm\Delta m is in kilograms and cc in m/s. Using Δm\Delta m in u or g/mol without converting gives an answer that is wrong by a large factor.

Common mistake: Mixing up fission and fusion

Fission divides (heavy nuclei split); fusion fuses (light nuclei join). Both release energy, but only fission is used in today’s power stations.

Notation note

  • u is the unified atomic mass unit, 1/12 of the mass of a carbon-12 atom (also written amu or Da).
  • A neutron is written X01X2021n\ce{^{1}_{0}n}; deuterium X12X2122H\ce{^{2}_{1}H} (also D) and tritium X13X2123H\ce{^{3}_{1}H} (also T).
  • A shortcut: 1 u of mass defect corresponds to 931.5 MeV.

Remember this

Remember this

  • Mass defect = mass of separate nucleons − mass of nucleus; binding energy E=Δm c2E = \Delta m\,c^2 (Δm in kg, c in m/s, E in J).
  • Binding energy per nucleon peaks near iron-56; fission of heavy and fusion of light nuclei both release energy.
  • Fission: U-235 + slow neutron → two fragments + 2–3 neutrons + about 200 MeV; chain reaction controlled by moderator and control rods.
  • Fusion: light nuclei join at millions of degrees; powers the Sun.

Test yourself

Check your understanding before moving on.

Flashcards

Nuclear Fission and Fusion: Flashcards

10 cards

  1. Question
    What is the mass defect of a nucleus?
    Answer

    Mass of the separate protons and neutrons minus the mass of the nucleus.

  2. Question
    What is binding energy?
    Answer

    The energy needed to separate a nucleus into its protons and neutrons, E = Δm c² (Δm in kg, c in m/s, E in J).

  3. Question
    Which nucleus is near the peak of the binding-energy-per-nucleon curve?
    Answer

    Iron-56 (about 8.8 MeV per nucleon): among the most stable nuclei.

  4. Question
    Why do both fission and fusion release energy?
    Answer

    Both form nuclei with a higher binding energy per nucleon (closer to iron); the extra binding energy is released.

  5. Question
    What is nuclear fission?
    Answer

    A heavy nucleus (e.g. uranium-235) splits into two medium nuclei, releasing 2–3 neutrons and about 200 MeV.

  6. Question
    What is a chain reaction, and what is the critical mass?
    Answer

    Neutrons from one fission cause further fissions. The critical mass is the smallest mass of fuel that sustains the chain.

  7. Question
    Roles of the moderator and the control rods in a reactor?
    Answer

    Moderator (water, graphite) slows neutrons. Control rods (boron, cadmium) absorb neutrons to control the rate.

  8. Question
    What is nuclear fusion?
    Answer

    Light nuclei join to form a heavier one, e.g. ²H + ³H → ⁴He + n. It needs millions of degrees.

  9. Question
    Why does fusion need such high temperatures?
    Answer

    The positively charged nuclei repel each other; they must collide very fast to get close enough to fuse.

  10. Question
    How do you convert u to kg, and MeV to J?
    Answer

    1 u = 1.66054 × 10⁻²⁷ kg; 1 MeV = 1.602 × 10⁻¹³ J (and 1 u of mass ≈ 931.5 MeV).

Quiz

Nuclear Fission and Fusion: Quiz

7 questions

  1. Question 1EasyThe mass of a nucleus compared with the total mass of its separate protons and neutrons is:
    Show answer

    Answer: smaller

    The difference is the mass defect, released as binding energy (E = Δm c²) when the nucleus formed.

  2. Question 2MediumComplete: ¹₀n + ²³⁵₉₂U → ¹⁴¹₅₆Ba + ⁹²₃₆Kr + ?
    Show answer

    Answer: 3 ¹₀n

    Mass numbers: 1 + 235 = 236 = 141 + 92 + 3. Atomic numbers: 92 = 56 + 36 + 0. So three neutrons.

  3. Question 3EasyWhich nucleus has the highest binding energy per nucleon?
    Show answer

    Answer: ⁵⁶Fe

    Iron-56 lies near the peak of the curve (about 8.8 MeV per nucleon); uranium-235 is about 7.6 and helium-4 about 7.1.

  4. Question 4EasyWhat is the job of the control rods in a nuclear reactor?
    Show answer

    Answer: to absorb neutrons and control the rate of fission

    Control rods (boron, cadmium) absorb neutrons. The moderator slows them; the coolant carries the heat.

  5. Question 5MediumWhy does fusion require temperatures of millions of degrees?
    Show answer

    Answer: to overcome the repulsion between positively charged nuclei

    Nuclei are positive and repel each other; only very fast collisions bring them close enough for the strong force to join them.

  6. Question 6MediumHow much energy is released when 1.00 × 10⁻³ kg of mass is converted completely (c = 2.998 × 10⁸ m/s)?
    Show answer

    Answer: 8.99 × 10¹³ J

    E = mc² = (1.00 × 10⁻³ kg)(2.998 × 10⁸ m/s)² = 8.99 × 10¹³ kg m²/s² = 8.99 × 10¹³ J.

  7. Question 7HardA mass defect of 0.0300 u corresponds to how much energy? (1 u = 931.5 MeV)
    Show answer

    Answer: 27.9 MeV

    0.0300 u × 931.5 MeV/u = 27.9 MeV.

Notes and downloads

  • Worksheet

    Nuclear Fission and Fusion Worksheet

    9 questions on mass defect, binding energy, E = mc², nuclear equations, reactors, and energy from fission, fusion and the Sun. Answer key included.

    IntermediateFree

References

  1. Brown, T. L.; LeMay, H. E., Jr.; Bursten, B. E.; Murphy, C. J.; Woodward, P. M.; Stoltzfus, M. W. Chemistry: The Central Science, 15th ed.; Pearson, 2022.

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