Significant Figures and Measurement

How do you count significant figures and use them in calculations?

BeginnerFoundationsLast reviewed 4 October 2026

What is it?

Every measurement has some uncertainty. A balance that reads 12.47 g is certain about 12.4 and estimates the last digit, 7. The significant figures (sig figs) in a number are all the digits known with certainty plus one estimated digit.

A measurement therefore has three parts: a number, a unit, and an implied uncertainty. 12.47 g and 12.5 g describe the same object, but the first was measured more precisely.

Key idea

The number of significant figures shows how precisely something was measured. A calculated answer can never be more precise than the measurements it came from.

Why does it matter?

  • Honest results. Writing 2.8409090 g/mL when your data supports only 2.84 g/mL claims a precision you don’t have.
  • Comparing data. Significant figures tell another scientist how far to trust your numbers.
  • Exams and lab reports. Answers are expected to the correct number of significant figures, with units.

How does it work?

1. Counting significant figures

RuleExampleSig figs
Non-zero digits are always significant4.56 g3
Zeros between non-zero digits are significant1.05 m3
Leading zeros (before the first non-zero digit) are not0.0042 L2
Trailing zeros after a decimal point are significant2.500 mL4
Trailing zeros in a whole number with no decimal point are ambiguous1200 m2, 3 or 4

Exact numbers have unlimited significant figures: counted numbers (3 beakers) and defined relationships (1 km = 1000 m; 1 in = 2.54 cm exactly). They never limit an answer.

2. Scientific notation

Scientific notation removes the ambiguity: every digit written in the first part is significant.

  • 0.000 520 m = 5.20×10−45.20 \times 10^{-4} m (3 sig figs)
  • 1200 m to 3 sig figs = 1.20×1031.20 \times 10^{3} m

3. Calculations

OperationRuleExample
× and ÷answer has the fewest significant figures of the inputs4.56 cm × 1.4 cm = 6.384 cm² → 6.4 cm² (2 s.f.)
+ and −answer has the fewest decimal places of the inputs25.12 g + 3.4 g = 28.52 g → 28.5 g (1 d.p.)

In a calculation with several steps, keep extra digits in the intermediate results and round only the final answer.

4. Rounding

Look at the digits you are dropping:

Dropped partRuleExample (to 3 s.f.)
less than half (starts with 0–4)keep the last digit0.0012349 m → 0.00123 m
more than half (5 followed by any non-zero digit, or 6–9)round up2.4562 g → 2.46 g
exactly half (5, 50, 500…)round to the even digit2.345 g → 2.34 g; 2.355 g → 2.36 g

The “round half to even” rule means that, over many results, exact halves are rounded up and down equally often, so averages are not pushed upward. Note that most calculators and spreadsheet ROUND functions always round an exact 5 up, so apply this rule yourself.

5. Accuracy, precision and replicate measurements

  • Accuracy: how close a result is to the true (accepted) value.
  • Precision: how close repeated measurements are to each other.

A single measurement cannot show its own precision. That’s why careful work uses replicate measurements: the same measurement repeated, usually in triplicate (3 times) or quintuplicate (5 times), or more. From the replicates:

xˉ=∑xins=∑(xi−xˉ)2n−1RSD=sxˉ×100%\begin{aligned} \bar{x} &= \frac{\sum x_i}{n} \\[6pt] s &= \sqrt{\frac{\sum (x_i - \bar{x})^2}{n - 1}} \\[6pt] \text{RSD} &= \frac{s}{\bar{x}} \times 100\% \end{aligned}
  • The mean, xˉ\bar{x}, is the best estimate of the value. Comparing it with the accepted value, xtruex_\text{true}, measures accuracy: error =xˉ−xtrue= \bar{x} - x_\text{true}, and percent error =xˉ−xtruextrue×100%= \dfrac{\bar{x} - x_\text{true}}{x_\text{true}} \times 100\%.
  • The standard deviation, ss, measures precision: a small ss means the replicates agree closely. The relative standard deviation (RSD) lets you compare the precision of results of different sizes.

Two kinds of error affect results. Random errors scatter replicates on both sides of the mean and lower precision. Systematic errors (for example a badly calibrated balance) shift every result the same way and lower accuracy, even when the precision is excellent.

Think of it like this

Measuring with a ruler marked only in centimetres is like reading a clock with only an hour hand: you can estimate “about half past”, but not the exact minute. A ruler marked in millimetres lets you estimate one more digit, so your measurement has one more significant figure.

More precisely

Significant figures are a simple way to show uncertainty. In research, uncertainty is stated explicitly, usually as the mean ± the standard deviation (for example 10.04 ± 0.02 mL, n = 5), and is combined through calculations using statistics. The standard deviation uses n−1n - 1 (the “sample” standard deviation) because the mean was calculated from the same data. With only two measurements it means little, which is why at least three replicates are recommended.

Visualise it

Four targets with five dots each. Accurate and precise: dots tightly grouped on the centre. Precise, not accurate: dots tightly grouped but off to one side. Accurate, not precise: dots spread out but averaging on the centre. Neither: dots spread out and off centre.
Accuracy is about hitting the true value; precision is about agreeing with each other.

Worked example

Worked example: Counting significant figures

Question: How many significant figures are in (a) 0.00420 g (b) 105.0 mL (c) 3.010×1053.010 \times 10^{5} J?

  1. 0.00420 g: leading zeros don’t count; the trailing zero after the decimal point does: 3.
  2. 105.0 mL: the zero between 1 and 5 counts, and so does the trailing zero after the decimal point: 4.
  3. 3.010×1053.010 \times 10^{5} J: every digit in 3.010 counts: 4.

Worked example: Multiplying and dividing

Question: A sample has a mass of 10.0 g and a volume of 3.52 mL. What is its density?

  1. ρ=mV=10.0 g3.52 mL=2.8409… g/mL\rho = \dfrac{m}{V} = \dfrac{10.0\ \text{g}}{3.52\ \text{mL}} = 2.8409\ldots\ \text{g/mL}
  2. Both inputs have 3 sig figs, so the answer has 3: 2.84 g/mL.

Worked example: Adding

Question: Masses of 12.0 g, 0.335 g and 4.5 g are added to a beaker. What is the total mass?

  1. 12.0 g+0.335 g+4.5 g=16.835 g12.0\ \text{g} + 0.335\ \text{g} + 4.5\ \text{g} = 16.835\ \text{g}
  2. The fewest decimal places is one (12.0 g and 4.5 g), so the answer is 16.8 g.

Worked example: Assessing accuracy and precision from replicates

Question: A student checks a 10.00 mL pipette by delivering water five times (quintuplicate) and finds the volumes 10.05 mL, 10.02 mL, 10.06 mL, 10.03 mL and 10.04 mL. Assess the accuracy and precision.

  1. Mean: the sum is 10.05 mL + 10.02 mL + 10.06 mL + 10.03 mL + 10.04 mL = 50.20 mL, so

    xˉ=50.20 mL5=10.04 mL\begin{aligned} \bar{x} &= \frac{50.20\ \text{mL}}{5} \\[4pt] &= 10.04\ \text{mL} \end{aligned}
  2. Deviations from the mean: +0.01 mL, −0.02 mL, +0.02 mL, −0.01 mL and 0.00 mL. Their squares are 0.0001 mL², 0.0004 mL², 0.0004 mL², 0.0001 mL² and 0.0000 mL², which add up to 0.0010 mL².

  3. Standard deviation:

    s=0.0010 mL25−1=0.016 mL\begin{aligned} s &= \sqrt{\frac{0.0010\ \text{mL}^2}{5 - 1}} \\[4pt] &= 0.016\ \text{mL} \end{aligned}
  4. RSD =0.016 mL10.04 mL×100%=0.16%= \dfrac{0.016\ \text{mL}}{10.04\ \text{mL}} \times 100\% = 0.16\% (the units of mL cancel): very precise.

  5. Error =10.04 mL−10.00 mL=+0.04 mL= 10.04\ \text{mL} - 10.00\ \text{mL} = +0.04\ \text{mL}, a percent error of +0.04 mL10.00 mL×100%=+0.4%\dfrac{+0.04\ \text{mL}}{10.00\ \text{mL}} \times 100\% = +0.4\%. The error is more than twice the standard deviation, so the pipette has a small systematic error: it delivers slightly too much.

Answer: 10.04±0.0210.04 \pm 0.02 mL (n = 5): precise, but slightly inaccurate.

Common mistake

Common mistake: Copying every digit from the calculator

100.0 g÷3.0 mL=33.333… g/mL100.0\ \text{g} \div 3.0\ \text{mL} = 33.333\ldots\ \text{g/mL}, but 3.0 mL has only 2 sig figs, so the answer is 33 g/mL.

Common mistake: Using the sig-fig rule for addition

For addition and subtraction, count decimal places, not significant figures: 6.38 cm − 2.1 cm = 4.28 cm → 4.3 cm.

Common mistake: Dropping significant zeros

A volume of a cube with side 2.00 cm is (2.00 cm)3=8.00 cm3(2.00\ \text{cm})^3 = 8.00\ \text{cm}^3, not 8 cm³. The zeros show the precision.

Notation note

  • “s.f.” or “sig figs” = significant figures; “d.p.” = decimal places.
  • A decimal point after a whole number, as in “100.” or “500. nm”, shows that the trailing zeros are significant (3 sig figs).

Remember this

Remember this

  • Sig figs = certain digits + one estimated digit. Leading zeros never count; trailing zeros after a decimal point always do.
  • × and ÷: fewest significant figures. + and −: fewest decimal places.
  • Exact numbers (counts, definitions) don’t limit precision. Round only the final answer; round an exact 5 to the even digit.
  • Accuracy: mean close to the true value (error). Precision: replicates close to each other (standard deviation).
  • Measure in replicate (at least triplicate) and report mean ± standard deviation with the number of measurements.

Test yourself

Check your understanding before moving on.

Flashcards

Significant Figures: Flashcards

14 cards

  1. Question
    What are significant figures?
    Answer

    The digits in a measurement that are known with certainty, plus one estimated digit.

  2. Question
    How many significant figures in 0.0042 L?
    Answer

    2 (leading zeros are not significant)

  3. Question
    How many significant figures in 2.500 mL?
    Answer

    4 (trailing zeros after a decimal point are significant)

  4. Question
    How many significant figures in 1.05 m?
    Answer

    3 (a zero between non-zero digits is significant)

  5. Question
    Rule for multiplying and dividing?
    Answer

    The answer has the fewest significant figures of the measured inputs.

  6. Question
    Rule for adding and subtracting?
    Answer

    The answer has the fewest decimal places of the measured inputs.

  7. Question
    Write 0.000 520 m in scientific notation.
    Answer

    5.20×10−45.20 \times 10^{-4} m (3 significant figures)

  8. Question
    Do exact numbers (such as 1 km = 1000 m) limit significant figures?
    Answer

    No. Exact numbers have unlimited significant figures.

  9. Question
    What is the difference between accuracy and precision?
    Answer

    Accuracy: closeness to the true value. Precision: closeness of repeated measurements to each other.

  10. Question
    25.12 g + 3.4 g = ?
    Answer

    28.5 g (one decimal place, like 3.4 g)

  11. Question
    Round 2.345 g and 2.355 g to three significant figures.
    Answer

    2.34 g and 2.36 g. An exact 5 is rounded to the even digit (round half to even).

  12. Question
    Why are measurements made in replicate (e.g. triplicate or quintuplicate)?
    Answer

    One measurement cannot show its precision. Replicates give a mean (best value) and a standard deviation (precision).

  13. Question
    Which statistic measures accuracy and which measures precision?
    Answer

    Accuracy: the error, mean − true value. Precision: the standard deviation (or relative standard deviation).

  14. Question
    Which kind of error lowers accuracy but not precision?
    Answer

    A systematic error, e.g. a badly calibrated balance shifts every result the same way.

Quiz

Significant Figures: Quiz

9 questions

  1. Question 1MediumHow many significant figures are in 0.03050 g?
    Show answer

    Answer: 4

    Leading zeros (0.0) do not count. 3, 0 (between non-zero digits), 5 and the trailing 0 after the decimal point do: 4.

  2. Question 2EasyWhat is 4.56 cm × 1.4 cm to the correct number of significant figures?
    Show answer

    Answer: 6.4 cm²

    4.56 cm × 1.4 cm = 6.384 cm². For multiplication, use the fewest significant figures: 1.4 cm has 2, so 6.4 cm².

  3. Question 3MediumWhat is 6.38 cm − 2.1 cm to the correct precision?
    Show answer

    Answer: 4.3 cm

    For subtraction, use the fewest decimal places: 2.1 cm has one, so 4.28 cm rounds to 4.3 cm.

  4. Question 4MediumRound 0.0012349 m to three significant figures.
    Show answer

    Answer: 0.00123 m

    The first three significant digits are 1, 2, 3. The next digit is 4 (less than 5), so the 3 stays: 0.00123 m.

  5. Question 5EasyA sample has mass 10.0 g and volume 3.52 mL. What is its density?
    Show answer

    Answer: 2.84 g/mL

    10.0 g ÷ 3.52 mL = 2.8409 g/mL. Both inputs have 3 significant figures, so 2.84 g/mL.

  6. Question 6MediumA student weighs a 5.000 g standard mass four times and gets 4.81 g, 4.80 g, 4.82 g and 4.81 g. The results are…
    Show answer

    Answer: precise but not accurate

    Mean = 4.81 g and standard deviation = 0.008 g, so the readings agree closely (precise). But the error is 4.81 g − 5.000 g = −0.19 g, far larger than the standard deviation (not accurate): a systematic error such as poor calibration.

  7. Question 7HardWhich number has exactly three significant figures without any ambiguity?
    Show answer

    Answer: 3.00 × 10² m

    In scientific notation every written digit counts: 3.00 has 3. "300 m" is ambiguous, 0.3 m has 1, and "3000." has 4.

  8. Question 8MediumUsing the round-half-to-even rule, what is 4.365 g to three significant figures?
    Show answer

    Answer: 4.36 g

    The dropped part is exactly 5, and the last kept digit (6) is already even, so it stays: 4.36 g. (4.375 g would round to 4.38 g.)

  9. Question 9MediumWhy are measurements usually repeated in triplicate or more?
    Show answer

    Answer: To calculate a mean and a standard deviation, which show the best value and the precision

    Replicates reveal random scatter (precision) and give a better mean. They cannot remove a systematic error: that needs calibration against an accepted value.

Notes and downloads

  • Worksheet

    Significant Figures Worksheet

    9 questions on counting significant figures, scientific notation, rounding and calculations with measurements. Answer key included.

    BeginnerFree

References

  1. Brown, T. L.; LeMay, H. E., Jr.; Bursten, B. E.; Murphy, C. J.; Woodward, P. M.; Stoltzfus, M. W. Chemistry: The Central Science, 15th ed.; Pearson, 2022.

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