Oxidation Numbers and Redox Reactions: Quiz
Seven questions on oxidation numbers, oxidizing and reducing agents and balancing redox equations, with explanations.
Oxidation Numbers and Redox Reactions: Quiz
7 questions
(+1) + x + 3(−2) = 0, so x = +5.
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Answer: +5
(+1) + x + 3(−2) = 0, so x = +5.
Cu²⁺ gains electrons (+2 → 0), so it is reduced and acts as the oxidizing agent. Zn is the reducing agent.
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Answer: Cu²⁺
Cu²⁺ gains electrons (+2 → 0), so it is reduced and acts as the oxidizing agent. Zn is the reducing agent.
2x + 7(−2) = −2, so 2x = +12 and x = +6. The answer +12 is the total for both Cr atoms.
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Answer: +6
2x + 7(−2) = −2, so 2x = +12 and x = +6. The answer +12 is the total for both Cr atoms.
In neutralization no oxidation number changes (Na +1, O −2, H +1, Cl −1 throughout). The others all transfer electrons.
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Answer: NaOH + HCl → NaCl + H₂O
In neutralization no oxidation number changes (Na +1, O −2, H +1, Cl −1 throughout). The others all transfer electrons.
Cu loses 2 electrons and each Fe³⁺ gains 1, so 2 Fe³⁺ are needed. Charge: +6 on the left, +4 + 2 = +6 on the right.
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Answer: 2Fe³⁺ + Cu → 2Fe²⁺ + Cu²⁺
Cu loses 2 electrons and each Fe³⁺ gains 1, so 2 Fe³⁺ are needed. Charge: +6 on the left, +4 + 2 = +6 on the right.
Mn goes from +7 to +2 (gains 5 electrons); each of the 5 Fe²⁺ loses 1 electron.
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Answer: 5
Mn goes from +7 to +2 (gains 5 electrons); each of the 5 Fe²⁺ loses 1 electron.
H₂O₂ is a peroxide: 2(+1) + 2x = 0, so x = −1.
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Answer: −1
H₂O₂ is a peroxide: 2(+1) + 2x = 0, so x = −1.