Quantum Numbers and Orbitals: Quiz
Seven questions on quantum numbers, allowed sets, counting orbitals and electrons, and orbital shapes, with explanations.
Quantum Numbers and Orbitals: Quiz
7 questions
The angular momentum quantum number l sets the shape: s (l = 0) spherical, p (l = 1) two lobes, d (l = 2) mostly four lobes.
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Answer: l
The angular momentum quantum number l sets the shape: s (l = 0) spherical, p (l = 1) two lobes, d (l = 2) mostly four lobes.
For d, l = 2, so mₗ = −2, −1, 0, +1, +2: five orbitals. 10 is the maximum number of electrons.
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Answer: 5
For d, l = 2, so mₗ = −2, −1, 0, +1, +2: five orbitals. 10 is the maximum number of electrons.
For n = 2, l can only be 0 or 1 (s or p). The first d subshell is 3d.
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Answer: 2d
For n = 2, l can only be 0 or 1 (s or p). The first d subshell is 3d.
Shell n holds 2n² electrons: 2 × 4² = 32 (4s 2 + 4p 6 + 4d 10 + 4f 14). 16 is the number of orbitals.
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Answer: 32
Shell n holds 2n² electrons: 2 × 4² = 32 (4s 2 + 4p 6 + 4d 10 + 4f 14). 16 is the number of orbitals.
For n = 3, l can be 2, and mₗ = −1 lies between −2 and +2. (3, 1, −2) has |mₗ| > l; (3, 3) has l = n; n cannot be 0.
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Answer: (3, 2, −1, +½)
For n = 3, l can be 2, and mₗ = −1 lies between −2 and +2. (3, 1, −2) has |mₗ| > l; (3, 3) has l = n; n cannot be 0.
l = 1 is a p subshell, and n = 4 is the shell: 4p, with 3 orbitals and up to 6 electrons.
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Answer: 4p
l = 1 is a p subshell, and n = 4 is the shell: 4p, with 3 orbitals and up to 6 electrons.
Radial nodes = n − l − 1 = 4 − 0 − 1 = 3. An s orbital has no angular nodes (l = 0), so all n − 1 = 3 nodes are radial.
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Answer: 3
Radial nodes = n − l − 1 = 4 − 0 − 1 = 3. An s orbital has no angular nodes (l = 0), so all n − 1 = 3 nodes are radial.