Phase Changes and Heating Curves: Quiz
Seven questions on phase changes, heating curves, enthalpies of phase change and boiling, with explanations.
Phase Changes and Heating Curves: Quiz
7 questions
In condensation, gas particles come together and attractions form, releasing energy. Melting, sublimation and vaporization absorb energy.
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Answer: Condensation
In condensation, gas particles come together and attractions form, releasing energy. Melting, sublimation and vaporization absorb energy.
Sublimation is solid → gas (e.g. dry ice). Deposition is the reverse, gas → solid.
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Answer: Sublimation
Sublimation is solid → gas (e.g. dry ice). Deposition is the reverse, gas → solid.
Heat is still being added, but it goes into changing state, so the temperature (average kinetic energy) does not rise.
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Answer: A phase change: energy overcomes intermolecular forces
Heat is still being added, but it goes into changing state, so the temperature (average kinetic energy) does not rise.
n = 10.0 g ÷ 46.07 g/mol = 0.2171 mol; q = 0.2171 mol × 38.6 kJ/mol = 8.38 kJ.
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Answer: 8.38 kJ
n = 10.0 g ÷ 46.07 g/mol = 0.2171 mol; q = 0.2171 mol × 38.6 kJ/mol = 8.38 kJ.
Both are at 100 °C, but condensing steam first releases 40.7 kJ/mol before cooling, giving many times more heat than the water alone.
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Answer: Steam releases its enthalpy of vaporization when it condenses on the skin
Both are at 100 °C, but condensing steam first releases 40.7 kJ/mol before cooling, giving many times more heat than the water alone.
Boiling starts when vapour bubbles can form inside the liquid, which happens once the vapour pressure equals the pressure above the liquid. 100 °C is only water's boiling point at 1 atm.
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Answer: its vapour pressure equals the external pressure
Boiling starts when vapour bubbles can form inside the liquid, which happens once the vapour pressure equals the pressure above the liquid. 100 °C is only water's boiling point at 1 atm.
Warm ice 0.418 kJ + melt (10.0 g ÷ 18.02 g/mol × 6.01 kJ/mol) 3.34 kJ + warm water 2.09 kJ = 5.85 kJ. 2.51 kJ leaves out the melting step.
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Answer: 5.85 kJ
Warm ice 0.418 kJ + melt (10.0 g ÷ 18.02 g/mol × 6.01 kJ/mol) 3.34 kJ + warm water 2.09 kJ = 5.85 kJ. 2.51 kJ leaves out the melting step.