pH: Quiz

7 questions

  1. Question 1EasyAt 25 °C, a solution has pH 9. It is…
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    Answer: basic

    At 25 °C, pH above 7 is basic, below 7 is acidic, and exactly 7 is neutral.

  2. Question 2MediumWhat is the pH of 0.0025 M nitric acid, HNOX3\ce{HNO3} (a strong acid)?
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    Answer: 2.60

    Strong acid, so [HX3OX+]=0.0025[\ce{H3O+}] = 0.0025 M and pH = −log(0.0025) = 2.60. The answer 11.40 is the pOH.

  3. Question 3MediumWhat is the pH of 0.15 M KOH (a strong base)?
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    Answer: 13.18

    [OHX−]=0.15[\ce{OH-}] = 0.15 M, so pOH = −log(0.15) = 0.82, and pH = 14.00 − 0.82 = 13.18. The answer 0.82 reports the pOH as the pH.

  4. Question 4MediumSolution A has pH 4 and solution B has pH 8. How do their HX3OX+\ce{H3O+} concentrations compare?
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    Answer: A has 10,000 times more

    A difference of 4 pH units is a factor of 10410^4 = 10,000, and the lower pH has the higher [HX3OX+][\ce{H3O+}].

  5. Question 5HardA solution has [OHX−]=2.5×10−4[\ce{OH-}] = 2.5 \times 10^{-4} M at 25 °C. What is its pH?
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    Answer: 10.40

    pOH = −log(2.5 × 10⁻⁴) = 3.60, so pH = 14.00 − 3.60 = 10.40. (Equivalently, [HX3OX+]=1.0×10−14÷2.5×10−4=4.0×10−11[\ce{H3O+}] = 1.0 \times 10^{-14} \div 2.5 \times 10^{-4} = 4.0 \times 10^{-11} M.)

  6. Question 6HardWhat is the pH of 0.020 M Ca(OH)X2\ce{Ca(OH)2}?
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    Answer: 12.60

    Each Ca(OH)X2\ce{Ca(OH)2} gives two OHX−\ce{OH-}: [OHX−]=0.040[\ce{OH-}] = 0.040 M, pOH = 1.40, pH = 12.60. The answer 12.30 forgets the factor of 2.

  7. Question 7Medium0.10 M HCl (pH 1.00) is diluted 10 times with water. What is the new pH?
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    Answer: 2.00

    Diluting 10 times gives 0.010 M HCl, and pH = −log(0.010) = 2.00. A 10-fold dilution of a strong acid raises the pH by 1.