NMR Spectroscopy: Quiz
Seven questions on hydrogen environments, chemical shift, integration and splitting, with explanations.
NMR Spectroscopy: Quiz
7 questions
Three hydrogen environments: CH₃, CH₂ and OH, in a 3 : 2 : 1 ratio.
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Answer: 3
Three hydrogen environments: CH₃, CH₂ and OH, in a 3 : 2 : 1 ratio.
n + 1 rule: 3 neighbouring H give 3 + 1 = 4 peaks (a quartet).
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Answer: 4
n + 1 rule: 3 neighbouring H give 3 + 1 = 4 peaks (a quartet).
Aldehyde hydrogens appear at 9–10 ppm. Alkyl H are around 1 ppm, O–CH₃ about 3.3–4.3 ppm, and TMS is 0.
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Answer: an aldehyde CHO
Aldehyde hydrogens appear at 9–10 ppm. Alkyl H are around 1 ppm, O–CH₃ about 3.3–4.3 ppm, and TMS is 0.
δ = 360 Hz ÷ 300 MHz = 1.20 ppm.
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Answer: 1.20 ppm
δ = 360 Hz ÷ 300 MHz = 1.20 ppm.
The two CH₃ groups are in different environments (next to C=O and on O). Neither has H on a neighbouring carbon, so both are singlets.
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Answer: Two singlets (3H each), at about 2.0 and 3.7 ppm
The two CH₃ groups are in different environments (next to C=O and on O). Neither has H on a neighbouring carbon, so both are singlets.
Each CH₃ is next to the CH, which has 1 H: 1 + 1 = 2 peaks. (The CH itself is split by 6 H into a septet.)
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Answer: Doublet
Each CH₃ is next to the CH, which has 1 H: 1 + 1 = 2 peaks. (The CH itself is split by 6 H into a septet.)
Two equivalent CH₃ (6H, doublet) next to one CH (septet, on C–O at 4.0 ppm), plus an OH singlet: (CH₃)₂CHOH.
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Answer: Propan-2-ol
Two equivalent CH₃ (6H, doublet) next to one CH (septet, on C–O at 4.0 ppm), plus an OH singlet: (CH₃)₂CHOH.