Light and Atomic Spectra: Quiz
Seven questions on wavelength, frequency, photon energy, line spectra and the Bohr model, with explanations.
Light and Atomic Spectra: Quiz
7 questions
c = λν, so a shorter wavelength means a higher frequency; E = hν, so the energy rises too.
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Answer: Both increase
c = λν, so a shorter wavelength means a higher frequency; E = hν, so the energy rises too.
Of these, ultraviolet has the shortest wavelength and therefore the highest photon energy, which is why it can damage skin.
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Answer: Ultraviolet
Of these, ultraviolet has the shortest wavelength and therefore the highest photon energy, which is why it can damage skin.
λ = c/ν = (2.998 × 10⁸ m/s) ÷ (98.1 × 10⁶ s⁻¹) = 3.06 m. Remember that 1 MHz = 10⁶ Hz.
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Answer: 3.06 m
λ = c/ν = (2.998 × 10⁸ m/s) ÷ (98.1 × 10⁶ s⁻¹) = 3.06 m. Remember that 1 MHz = 10⁶ Hz.
E = hc/λ = (6.626 × 10⁻³⁴ J s × 2.998 × 10⁸ m/s) ÷ (450 × 10⁻⁹ m) = 4.41 × 10⁻¹⁹ J. 4.41 × 10⁻²⁸ J results from leaving λ in nm.
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Answer: 4.41 × 10⁻¹⁹ J
E = hc/λ = (6.626 × 10⁻³⁴ J s × 2.998 × 10⁸ m/s) ÷ (450 × 10⁻⁹ m) = 4.41 × 10⁻¹⁹ J. 4.41 × 10⁻²⁸ J results from leaving λ in nm.
Each line is a photon emitted when an electron drops between two allowed energy levels. The levels are different in every element, so the pattern of lines is unique.
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Answer: Its electrons can only have certain energies, which differ from element to element
Each line is a photon emitted when an electron drops between two allowed energy levels. The levels are different in every element, so the pattern of lines is unique.
ΔE = 2.179 × 10⁻¹⁸ J × (1/2² − 1/4²) = 4.086 × 10⁻¹⁹ J, and λ = hc/ΔE = 486 nm. The drop from 3 to 2 gives 656 nm.
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Answer: n = 4 to n = 2
ΔE = 2.179 × 10⁻¹⁸ J × (1/2² − 1/4²) = 4.086 × 10⁻¹⁹ J, and λ = hc/ΔE = 486 nm. The drop from 3 to 2 gives 656 nm.
2.179 × 10⁻¹⁸ J per atom × 6.022 × 10²³ mol⁻¹ = 1.312 × 10⁶ J/mol = 1312 kJ/mol. 328 kJ/mol would be from n = 2.
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Answer: 1312 kJ/mol
2.179 × 10⁻¹⁸ J per atom × 6.022 × 10²³ mol⁻¹ = 1.312 × 10⁶ J/mol = 1312 kJ/mol. 328 kJ/mol would be from n = 2.