Le Chatelier's Principle: Quiz
Seven questions on how concentration, pressure, temperature and catalysts affect equilibria, with explanations.
Le Chatelier's Principle: Quiz
7 questions
Removing a product makes Q smaller than K, so the reaction goes forward to replace some of it. K is unchanged.
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Answer: The equilibrium shifts right, making more NH₃
Removing a product makes Q smaller than K, so the reaction goes forward to replace some of it. K is unchanged.
Higher pressure favours fewer moles of gas: 2 mol → 1 mol. HI: no change (2 = 2). The other two have more gas on the right, so they shift left.
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Answer:
Higher pressure favours fewer moles of gas: 2 mol → 1 mol. HI: no change (2 = 2). The other two have more gas on the right, so they shift left.
Heat is a "product" of an exothermic reaction. Adding heat shifts the equilibrium left, and K itself becomes smaller.
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Answer: Shifts left and decreases K
Heat is a "product" of an exothermic reaction. Adding heat shifts the equilibrium left, and K itself becomes smaller.
A catalyst speeds up the forward and reverse reactions equally, so the position of equilibrium and K are unchanged.
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Answer: Equilibrium is reached faster, with the same composition
A catalyst speeds up the forward and reverse reactions equally, so the position of equilibrium and K are unchanged.
Concentration and pressure changes shift the position but leave K unchanged. Only temperature changes K.
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Answer: Changing the temperature
Concentration and pressure changes shift the position but leave K unchanged. Only temperature changes K.
The forward reaction is endothermic. Cooling favours the exothermic reverse reaction, forming more colourless N₂O₄, so the brown colour fades.
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Answer: It becomes paler
The forward reaction is endothermic. Cooling favours the exothermic reverse reaction, forming more colourless N₂O₄, so the brown colour fades.
Q = (0.156 M)² / ((0.122 M)(0.0222 M)) = 8.99. Q < K, so the reaction goes forward, using up H₂ and I₂.
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Answer: 8.99
Q = (0.156 M)² / ((0.122 M)(0.0222 M)) = 8.99. Q < K, so the reaction goes forward, using up H₂ and I₂.