Hydrocarbons and Naming Alkanes: Quiz
Seven questions on hydrocarbon formulas, IUPAC names, isomers, boiling points and combustion, with explanations.
Hydrocarbons and Naming Alkanes: Quiz
7 questions
Alkanes have only single bonds, so each carbon carries the maximum number of hydrogens: CₙH₂ₙ₊₂ (e.g. C₃H₈). CₙH₂ₙ is the alkenes and CₙH₂ₙ₋₂ the alkynes.
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Answer: CₙH₂ₙ₊₂
Alkanes have only single bonds, so each carbon carries the maximum number of hydrogens: CₙH₂ₙ₊₂ (e.g. C₃H₈). CₙH₂ₙ is the alkenes and CₙH₂ₙ₋₂ the alkynes.
Hept- means 7 carbons; for an alkane, H = 2(7) + 2 = 16.
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Answer: C₇H₁₆
Hept- means 7 carbons; for an alkane, H = 2(7) + 2 = 16.
The longest chain has 5 carbons. Numbering from the end nearer the branch puts the methyl on carbon 2, not 4. (Hexane is an isomer, but it is the unbranched chain.)
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Answer: 2-methylpentane
The longest chain has 5 carbons. Numbering from the end nearer the branch puts the methyl on carbon 2, not 4. (Hexane is an isomer, but it is the unbranched chain.)
Pentane, 2-methylbutane and 2,2-dimethylpropane.
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Answer: 3
Pentane, 2-methylbutane and 2,2-dimethylpropane.
2-Ethylbutane and 1-methylbutane miss the longest chain (they are 3-methylpentane and pentane). "2-dimethyl" needs two locants: 2,2-dimethylpropane.
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Answer: 3-methylpentane
2-Ethylbutane and 1-methylbutane miss the longest chain (they are 3-methylpentane and pentane). "2-dimethyl" needs two locants: 2,2-dimethylpropane.
Pentane is the largest unbranched molecule here: it has the most surface contact and the strongest dispersion forces (36 °C). Branching lowers the boiling point, and butane is smaller.
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Answer: pentane
Pentane is the largest unbranched molecule here: it has the most surface contact and the strongest dispersion forces (36 °C). Branching lowers the boiling point, and butane is smaller.
1 mol C₄H₁₀ × (13 mol O₂ / 2 mol C₄H₁₀) = 6.5 mol O₂.
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Answer: 6.5 mol
1 mol C₄H₁₀ × (13 mol O₂ / 2 mol C₄H₁₀) = 6.5 mol O₂.