Gas Mixtures and Gas Stoichiometry: Quiz
Seven questions on partial pressures, mole fractions, gases collected over water and gas stoichiometry, with explanations.
Gas Mixtures and Gas Stoichiometry: Quiz
7 questions
Dalton's law: P(total) = 0.60 atm + 0.25 atm + 0.15 atm = 1.00 atm.
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Answer: 1.00 atm
Dalton's law: P(total) = 0.60 atm + 0.25 atm + 0.15 atm = 1.00 atm.
P(He) = x(He) × P(total) = 0.40 × 2.0 atm = 0.80 atm.
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Answer: 0.80 atm
P(He) = x(He) × P(total) = 0.40 × 2.0 atm = 0.80 atm.
P(O₂) = P(total) − P(H₂O) = 760 mmHg − 23.8 mmHg = 736.2 mmHg.
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Answer: 736.2 mmHg
P(O₂) = P(total) − P(H₂O) = 760 mmHg − 23.8 mmHg = 736.2 mmHg.
0.500 mol × 22.4 L/mol = 11.2 L. 12.2 L would be the volume at 25 °C (24.5 L/mol).
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Answer: 11.2 L
0.500 mol × 22.4 L/mol = 11.2 L. 12.2 L would be the volume at 25 °C (24.5 L/mol).
For gases at the same T and P, volumes are in the mole ratio: 1 N₂ : 2 NH₃, so 10.0 L × 2 = 20.0 L.
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Answer: 20.0 L
For gases at the same T and P, volumes are in the mole ratio: 1 N₂ : 2 NH₃, so 10.0 L × 2 = 20.0 L.
n(Zn) = 1.31 g ÷ 65.38 g/mol = 0.0200 mol = n(H₂). V = nRT/P = 0.0200 mol × 0.08206 L·atm/(mol·K) × 298.15 K ÷ 1.00 atm = 0.490 L. 0.449 L uses 22.4 L/mol at the wrong temperature.
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Answer: 0.490 L
n(Zn) = 1.31 g ÷ 65.38 g/mol = 0.0200 mol = n(H₂). V = nRT/P = 0.0200 mol × 0.08206 L·atm/(mol·K) × 298.15 K ÷ 1.00 atm = 0.490 L. 0.449 L uses 22.4 L/mol at the wrong temperature.
By Dalton's law the measured pressure is the sum of the gas pressure and the water vapour pressure, so the vapour pressure is subtracted.
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Answer: The collected gas is mixed with water vapour, which contributes to the total pressure
By Dalton's law the measured pressure is the sum of the gas pressure and the water vapour pressure, so the vapour pressure is subtracted.