Electrolysis: Quiz
Seven questions on electrode signs, predicting products, industrial electrolysis and Faraday's-law calculations, with explanations.
Electrolysis: Quiz
7 questions
Oxidation always happens at the anode; in electrolysis it is connected to the positive terminal.
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Answer: positive, where oxidation happens
Oxidation always happens at the anode; in electrolysis it is connected to the positive terminal.
Potassium is far more reactive than hydrogen, so water is reduced: 2H₂O + 2e⁻ → H₂ + 2OH⁻.
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Answer: hydrogen
Potassium is far more reactive than hydrogen, so water is reduced: 2H₂O + 2e⁻ → H₂ + 2OH⁻.
Sulfate is not discharged; water is oxidized: 2H₂O → O₂ + 4H⁺ + 4e⁻. Copper forms at the cathode.
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Answer: oxygen
Sulfate is not discharged; water is oxidized: 2H₂O → O₂ + 4H⁺ + 4e⁻. Copper forms at the cathode.
Na⁺ is very hard to reduce; in water, hydrogen forms at the cathode instead.
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Answer: in solution, water is reduced instead of Na⁺
Na⁺ is very hard to reduce; in water, hydrogen forms at the cathode instead.
Q = 1.00 C/s × 965 s = 965 C; n = 965 C ÷ 96 485 C/mol = 0.0100 mol.
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Answer: 0.0100 mol
Q = 1.00 C/s × 965 s = 965 C; n = 965 C ÷ 96 485 C/mol = 0.0100 mol.
0.0300 mol Ag needs 0.0300 mol e⁻; Cu²⁺ needs 2 e⁻ per atom, so 0.0300 ÷ 2 = 0.0150 mol Cu.
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Answer: 0.0150 mol
0.0300 mol Ag needs 0.0300 mol e⁻; Cu²⁺ needs 2 e⁻ per atom, so 0.0300 ÷ 2 = 0.0150 mol Cu.
The impure anode is oxidized and dissolves (Cu → Cu²⁺ + 2e⁻); pure copper is deposited on the cathode.
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Answer: the anode
The impure anode is oxidized and dissolves (Cu → Cu²⁺ + 2e⁻); pure copper is deposited on the cathode.