Density: Quiz
Seven questions on calculating and measuring density, floating and sinking, and replicate results, with explanations.
Density: Quiz
7 questions
Density is mass per unit volume, so ρ = m / V. Check the units: g ÷ cm³ gives g/cm³.
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Answer: ρ = m / V
Density is mass per unit volume, so ρ = m / V. Check the units: g ÷ cm³ gives g/cm³.
ρ = 54.0 g ÷ 20.0 cm³ = 2.70 g/cm³. 0.370 is the fraction upside down (cm³/g).
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Answer: 2.70 g/cm³
ρ = 54.0 g ÷ 20.0 cm³ = 2.70 g/cm³. 0.370 is the fraction upside down (cm³/g).
The volume of the object is the rise in level: 45.2 mL − 30.0 mL = 15.2 mL (= 15.2 cm³).
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Answer: 15.2 mL
The volume of the object is the rise in level: 45.2 mL − 30.0 mL = 15.2 mL (= 15.2 cm³).
20.0 g ÷ 25.0 cm³ = 0.800 g/cm³, less than water, so it floats. The others are 1.20 g/cm³, 5.00 g/cm³ and 3.00 g/cm³: all sink.
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Answer: Mass 20.0 g, volume 25.0 cm³
20.0 g ÷ 25.0 cm³ = 0.800 g/cm³, less than water, so it floats. The others are 1.20 g/cm³, 5.00 g/cm³ and 3.00 g/cm³: all sink.
m = ρV = 0.789 g/mL × 200. mL = 157.8 g, which is 158 g to 3 significant figures. 253 g comes from dividing (200. ÷ 0.789).
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Answer: 158 g
m = ρV = 0.789 g/mL × 200. mL = 157.8 g, which is 158 g to 3 significant figures. 253 g comes from dividing (200. ÷ 0.789).
Ice (0.917 g/cm³) is less dense than liquid water (about 1.00 g/mL) because water molecules are held further apart in the ice structure. Floating depends on density, not on mass.
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Answer: Ice is less dense than liquid water
Ice (0.917 g/cm³) is less dense than liquid water (about 1.00 g/mL) because water molecules are held further apart in the ice structure. Floating depends on density, not on mass.
Mean = 13.50 g/cm³ ÷ 5 = 2.70 g/cm³. Sample standard deviation s = 0.016 g/cm³, which rounds to 0.02 g/cm³. ±0.04 is the range (2.72 − 2.68), not the standard deviation.
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Answer: 2.70 ± 0.02 g/cm³ (n = 5)
Mean = 13.50 g/cm³ ÷ 5 = 2.70 g/cm³. Sample standard deviation s = 0.016 g/cm³, which rounds to 0.02 g/cm³. ±0.04 is the range (2.72 − 2.68), not the standard deviation.