Entropy and Gibbs Free Energy: Quiz

7 questions

  1. Question 1EasyWhich process has a negative ΔS?
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    Answer: 2SO₂(g) + O₂(g) → 2SO₃(g)

    3 mol of gas become 2 mol, so the entropy decreases. The others increase disorder or the moles of gas.

  2. Question 2MediumΔH = +50.0 kJ and ΔS = +0.200 kJ/K. Above what temperature is the reaction spontaneous?
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    Answer: 250. K

    T = ΔH ÷ ΔS = 50.0 kJ ÷ 0.200 kJ/K = 250. K. Above this, TΔS outweighs ΔH.

  3. Question 3EasyA reaction has ΔH negative and ΔS positive. It is spontaneous:
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    Answer: at all temperatures

    ΔG = ΔH − TΔS = (negative) − (positive) is negative for every T.

  4. Question 4MediumCalculate ΔG at 300. K for ΔH = −100. kJ and ΔS = −200. J/K.
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    Answer: −40.0 kJ

    ΔS = −0.200 kJ/K; ΔG = −100. kJ − (300. K)(−0.200 kJ/K) = −100. kJ + 60.0 kJ = −40.0 kJ. Forgetting to convert J to kJ gives the large wrong answer.

  5. Question 5MediumIf ΔG° for a reaction is positive, the equilibrium constant K is:
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    Answer: less than 1

    ΔG° = −RT ln K: positive ΔG° means ln K is negative, so K is less than 1 (reactants favoured).

  6. Question 6MediumWhy must limestone be heated strongly to make lime?
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    Answer: ΔH and ΔS are both positive, so ΔG is only negative at high T

    For CaCO₃ → CaO + CO₂, ΔH = +179.2 kJ and ΔS = +160.2 J/K, so ΔG becomes negative above about 1119 K.

  7. Question 7HardWhich statement about a spontaneous reaction is correct?
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    Answer: it increases the total entropy of the universe

    That is the second law. Spontaneous reactions can be slow and can be endothermic (e.g. ice melting at 25 °C).