The Gas Laws: Quiz

7 questions

  1. Question 1EasyAt constant temperature, the volume of a gas is halved. What happens to its pressure?
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    Answer: It doubles

    Boyle's law: P × V stays constant, so halving V doubles P.

  2. Question 2MediumA gas at constant pressure is heated from 100 °C to 200 °C. By what factor does its volume change?
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    Answer: 1.27

    Use kelvin: 100 °C = 373 K and 200 °C = 473 K. V₂/V₁ = 473 K ÷ 373 K = 1.27 (the units cancel). Doubling the Celsius number does not double the temperature.

  3. Question 3EasyWhich temperature must be used in gas law calculations?
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    Answer: Kelvin

    Gas laws need an absolute scale that starts at zero. Even if both temperatures are in °C, the ratio is wrong.

  4. Question 4MediumA sealed can contains gas at 1.00 atm and 27 °C. It is heated to 327 °C. What is the new pressure?
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    Answer: 2.00 atm

    Gay-Lussac: T₁ = 27 °C + 273 = 300 K and T₂ = 327 °C + 273 = 600 K. P₂ = 1.00 atm × (600 K ÷ 300 K) = 2.00 atm. (Using °C would give 12.1 atm, which is wrong.)

  5. Question 5MediumWhat is the pressure of 0.200 mol of gas in a 10.0 L container at 27 °C? (R = 8.314 L·kPa/(mol·K))
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    Answer: 49.9 kPa

    T = 27 °C + 273.15 = 300.15 K. P = nRT/V = (0.200 mol × 8.314 L·kPa/(mol·K) × 300.15 K) ÷ 10.0 L = 49.9 kPa. The units of mol, K and L cancel, leaving kPa.

  6. Question 6MediumAt the same temperature and pressure, 2 mol of nitrogen and 2 mol of helium occupy…
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    Answer: the same volume

    Avogadro's law: equal moles of ideal gases at the same T and P occupy equal volumes, whatever the gas.

  7. Question 7HardUnder which conditions does a real gas behave most like an ideal gas?
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    Answer: Low pressure and high temperature

    Then the particles are far apart and fast, so their own volume and the attractions between them matter least.