The Gas Laws: Quiz
Seven questions on the gas laws, kelvin temperatures and the ideal gas law, with explanations.
The Gas Laws: Quiz
7 questions
Boyle's law: P × V stays constant, so halving V doubles P.
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Answer: It doubles
Boyle's law: P × V stays constant, so halving V doubles P.
Use kelvin: 100 °C = 373 K and 200 °C = 473 K. V₂/V₁ = 473 K ÷ 373 K = 1.27 (the units cancel). Doubling the Celsius number does not double the temperature.
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Answer: 1.27
Use kelvin: 100 °C = 373 K and 200 °C = 473 K. V₂/V₁ = 473 K ÷ 373 K = 1.27 (the units cancel). Doubling the Celsius number does not double the temperature.
Gas laws need an absolute scale that starts at zero. Even if both temperatures are in °C, the ratio is wrong.
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Answer: Kelvin
Gas laws need an absolute scale that starts at zero. Even if both temperatures are in °C, the ratio is wrong.
Gay-Lussac: T₁ = 27 °C + 273 = 300 K and T₂ = 327 °C + 273 = 600 K. P₂ = 1.00 atm × (600 K ÷ 300 K) = 2.00 atm. (Using °C would give 12.1 atm, which is wrong.)
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Answer: 2.00 atm
Gay-Lussac: T₁ = 27 °C + 273 = 300 K and T₂ = 327 °C + 273 = 600 K. P₂ = 1.00 atm × (600 K ÷ 300 K) = 2.00 atm. (Using °C would give 12.1 atm, which is wrong.)
T = 27 °C + 273.15 = 300.15 K. P = nRT/V = (0.200 mol × 8.314 L·kPa/(mol·K) × 300.15 K) ÷ 10.0 L = 49.9 kPa. The units of mol, K and L cancel, leaving kPa.
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Answer: 49.9 kPa
T = 27 °C + 273.15 = 300.15 K. P = nRT/V = (0.200 mol × 8.314 L·kPa/(mol·K) × 300.15 K) ÷ 10.0 L = 49.9 kPa. The units of mol, K and L cancel, leaving kPa.
Avogadro's law: equal moles of ideal gases at the same T and P occupy equal volumes, whatever the gas.
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Answer: the same volume
Avogadro's law: equal moles of ideal gases at the same T and P occupy equal volumes, whatever the gas.
Then the particles are far apart and fast, so their own volume and the attractions between them matter least.
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Answer: Low pressure and high temperature
Then the particles are far apart and fast, so their own volume and the attractions between them matter least.