Solubility and Colligative Properties: Quiz
Seven questions on solubility, molality, freezing-point depression, boiling-point elevation and osmotic pressure, with explanations.
Solubility and Colligative Properties: Quiz
7 questions
Gas solubility falls as temperature rises, so CO₂ escapes faster from a warm drink.
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Answer: gases are less soluble when warm
Gas solubility falls as temperature rises, so CO₂ escapes faster from a warm drink.
m = 0.500 mol ÷ 0.250 kg = 2.00 mol/kg. Remember to convert grams to kilograms.
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Answer: 2.00 mol/kg
m = 0.500 mol ÷ 0.250 kg = 2.00 mol/kg. Remember to convert grams to kilograms.
CaCl₂ gives 3 ions (i = 3), the most particles, so the largest freezing-point depression.
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Answer: CaCl₂
CaCl₂ gives 3 ions (i = 3), the most particles, so the largest freezing-point depression.
ΔTf = 1 × 1.86 °C kg/mol × 1.00 mol/kg = 1.86 °C; 0.00 °C − 1.86 °C = −1.86 °C.
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Answer: −1.86 °C
ΔTf = 1 × 1.86 °C kg/mol × 1.00 mol/kg = 1.86 °C; 0.00 °C − 1.86 °C = −1.86 °C.
Na₂SO₄ → 2Na⁺ + SO₄²⁻: three ions. The sulfate ion stays together.
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Answer: 3
Na₂SO₄ → 2Na⁺ + SO₄²⁻: three ions. The sulfate ion stays together.
R = 0.08206 L atm mol⁻¹ K⁻¹ contains kelvin, so T must be in kelvin for the units to cancel.
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Answer: K
R = 0.08206 L atm mol⁻¹ K⁻¹ contains kelvin, so T must be in kelvin for the units to cancel.
Molality uses mass of solvent, which does not change on heating; volumes expand, so molarity changes.
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Answer: molality does not change with temperature
Molality uses mass of solvent, which does not change on heating; volumes expand, so molarity changes.