Buffers: Quiz
Seven questions on how buffers work and buffer pH calculations, with explanations.
Buffers: Quiz
7 questions
A buffer needs a weak acid and its conjugate base. Acetic acid is weak and acetate is its conjugate base. HCl/NaCl does not buffer because Cl⁻ is too weak a base.
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Answer: Acetic acid and sodium acetate
A buffer needs a weak acid and its conjugate base. Acetic acid is weak and acetate is its conjugate base. HCl/NaCl does not buffer because Cl⁻ is too weak a base.
With [A⁻] = [HA], log(1) = 0, so pH = pKa = 4.74.
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Answer: 4.74
With [A⁻] = [HA], log(1) = 0, so pH = pKa = 4.74.
pH = 4.74 + log(0.20/0.10) = 4.74 + 0.30 = 5.04. The answer 4.44 puts the ratio upside down.
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Answer: 5.04
pH = 4.74 + log(0.20/0.10) = 4.74 + 0.30 = 5.04. The answer 4.44 puts the ratio upside down.
pH = 4.74 + log(0.10/0.20) = 4.74 − 0.30 = 4.44. More acid than base gives a pH below the pKa.
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Answer: 4.44
pH = 4.74 + log(0.10/0.20) = 4.74 − 0.30 = 4.44. More acid than base gives a pH below the pKa.
OH⁻ reacts with acetic acid: HA = 0.09 mol, A⁻ = 0.11 mol. pH = 4.74 + log(0.11/0.09) = 4.83. The pH rises only slightly.
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Answer: 4.83
OH⁻ reacts with acetic acid: HA = 0.09 mol, A⁻ = 0.11 mol. pH = 4.74 + log(0.11/0.09) = 4.83. The pH rises only slightly.
Choose a pair whose pKa is within about 1 unit of the target pH. 9.25 is close to 9.5.
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Answer: Ammonium/ammonia (pKa 9.25)
Choose a pair whose pKa is within about 1 unit of the target pH. 9.25 is close to 9.5.
. The base part of the buffer neutralizes added acid; the acid part neutralizes added base.
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Answer: The conjugate base, A⁻
. The base part of the buffer neutralizes added acid; the acid part neutralizes added base.