Spectrophotometry and Beer's Law: Quiz
Seven questions on absorbance, transmittance, Beer's law calculations and calibration curves, with explanations.
Spectrophotometry and Beer's Law: Quiz
7 questions
T = 0.500, so A = −log(0.500) = 0.301. Using 50.0 instead of 0.500 gives −1.70, which is impossible for a real sample.
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Answer: 0.301
T = 0.500, so A = −log(0.500) = 0.301. Using 50.0 instead of 0.500 gives −1.70, which is impossible for a real sample.
Beer's law, A = εbc: A is directly proportional to c.
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Answer: doubles
Beer's law, A = εbc: A is directly proportional to c.
A has no unit, so ε = A ÷ (b × c) has units 1 ÷ (cm × mol/L) = L mol⁻¹ cm⁻¹.
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Answer: L mol⁻¹ cm⁻¹
A has no unit, so ε = A ÷ (b × c) has units 1 ÷ (cm × mol/L) = L mol⁻¹ cm⁻¹.
c = A ÷ (εb) = 0.450 ÷ (1.50 × 10⁴ L mol⁻¹ cm⁻¹ × 1.00 cm) = 3.00 × 10⁻⁵ mol/L.
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Answer: 3.00 × 10⁻⁵ mol/L
c = A ÷ (εb) = 0.450 ÷ (1.50 × 10⁴ L mol⁻¹ cm⁻¹ × 1.00 cm) = 3.00 × 10⁻⁵ mol/L.
The blank contains everything except the analyte, so absorption by the solvent, reagents and cell is subtracted.
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Answer: to zero the instrument so that only the analyte absorbance is measured
The blank contains everything except the analyte, so absorption by the solvent, reagents and cell is subtracted.
A is proportional to the path length b: doubling b doubles A.
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Answer: 0.500
A is proportional to the path length b: doubling b doubles A.
The reading must fall inside the calibration range; Beer's law may not hold at high absorbance. A longer cell would raise A even further.
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Answer: dilute the unknown by a known factor, measure again and multiply by the factor
The reading must fall inside the calibration range; Beer's law may not hold at high absorbance. A longer cell would raise A even further.